11n^2-141n+448=0

Solution for 11n^2-141n+448=0 equation:

11n^2-141n+448=0

a = 11; b = -141; c = +448;
Δ = b2-4ac
Δ = -1412-4·11·448
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-141)-13}{2*11}=\frac{128}{22}
=5+9/11
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-141)+13}{2*11}=\frac{154}{22}
=7
$